# Copyright 2019 Google LLC
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#      http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
"""Helpers for sending mail."""
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import Mail

from config import db_config
from metrics import logs


def send(to_email, subject, html_content):
  """Send email."""
  sendgrid_api_key = db_config.get_value('sendgrid_api_key')
  if not sendgrid_api_key:
    logs.log_warn('Skipping email as SendGrid API key is not set in config.')
    return

  from_email = db_config.get_value('sendgrid_sender')
  if not from_email:
    logs.log_warn('Skipping email as SendGrid sender is not set in config.')
    return

  message = Mail(
      from_email=str(from_email),
      to_emails=str(to_email),
      subject=subject,
      html_content=str(html_content))
  try:
    sg = SendGridAPIClient(sendgrid_api_key)
    response = sg.send(message)
    logs.log(
        'Sent email to %s.' % to_email,
        status_code=response.status_code,
        body=response.body,
        headers=response.headers)
  except Exception:
    logs.log_error('Failed to send email to %s.' % to_email)
